What is the directrix x^2=-10y ?

The directrix x^2=-10y is y= 5/2

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directrix x^2=-10y

directrix

x^{2} = - 10 y

y = \frac{5}{2}

Solution steps

Rewrite

x^{2} = - 10 y

in the standard form:

4 (- \frac{5}{2}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{5}{2}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{5}{2})

Refine

y = \frac{5}{2}

x^{2} - 4

y = 2 x^{2} - 13 x - 7

x = 7 y^{2}

y = 7 x^{2} - 9 x - 5

y = 3 x^{2} - 5 x 7