What is the directrix-2x^2+25x ?

The directrix-2x^2+25x is y= 313/4

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directrix-2x^2+25x

directrix

- 2 x^{2} + 25 x

y = \frac{313}{4}

Solution steps

Rewrite

y = - 2 x^{2} + 25 x

in the standard form

4 (- \frac{1}{8}) (y - \frac{625}{8}) = (x - \frac{25}{4})^{2}

(h, k) = (\frac{25}{4}, \frac{625}{8}), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{25}{4}, \frac{625}{8})

y-coordinate

y = \frac{625}{8} - p

y = \frac{625}{8} - (- \frac{1}{8})

Refine

y = \frac{313}{4}

4 t^{2} + 1

y = (x + 5)^{2}

y = 3 x^{2} - 2

y = 3 x^{2} - 5

x^{2} + 4 x + 4 y - 4 = 0