What is the directrix y=x^2-7 ?

The directrix y=x^2-7 is y=-29/4

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directrix y=x^2-7

directrix

y = x^{2} - 7

y = - \frac{29}{4}

Solution steps

Rewrite

y = x^{2} - 7

in the standard form:

4 \cdot \frac{1}{4} (y - (- 7)) = (x - 0)^{2}

(h, k) = (0, - 7), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 7)

y-coordinate

y = - 7 - p

y = - 7 - \frac{1}{4}

Refine

y = - \frac{29}{4}

2 x - 5 x^{2}

y^{2} - 6 x - 6 y + 3 = 0

y = 3 x^{2} - 31 x + 56 - (x - 8)

x^{2} - 5 x + 6

y = (x - 4)^{2}