What is the directrix (y+3)^2=4(x-3) ?

The directrix (y+3)^2=4(x-3) is x=2

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directrix (y+3)^2=4(x-3)

directrix

(y + 3)^{2} = 4 (x - 3)

x = 2

Solution steps

Rewrite

(y + 3)^{2} = 4 (x - 3)

in the standard form:

4 \cdot 1 \cdot (x - 3) = (y - (- 3))^{2}

(h, k) = (3, - 3), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(3, - 3)

x-coordinate

x = 3 - p

x = 3 - 1

Refine

x = 2

25 x^{2} - 70 x + 36

y = x^{2} - 5 x - 6

y^{2} + 8 y + 4 x + 20 = 0

- x^{2} + 4

y = + 2 (x + 1)^{2} - 5