What is the directrix x+y^2=0 ?

The directrix x+y^2=0 is x= 1/4

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directrix x+y^2=0

directrix

x + y^{2} = 0

x = \frac{1}{4}

Solution steps

Rewrite

x + y^{2} = 0

in the standard form:

4 (- \frac{1}{4}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{4})

Refine

x = \frac{1}{4}

y = x^{2} - 4 x 3

y^{2} + 16 x = 0

y^{2} + 28 x = 0

y = 4 x^{2} - 24 x + 31

y = - x^{2} + 4 x