What is the directrix y=x^2-6x+5 ?

The directrix y=x^2-6x+5 is y=-17/4

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directrix y=x^2-6x+5

directrix

y = x^{2} - 6 x + 5

y = - \frac{17}{4}

Solution steps

Rewrite

y = x^{2} - 6 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - 3)^{2}

(h, k) = (3, - 4), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, - 4)

y-coordinate

y = - 4 - p

y = - 4 - \frac{1}{4}

Refine

y = - \frac{17}{4}

2 x^{2} - 19 x + 9

(x + 3)^{2} = - y

x^{2} + 4

x^{2} - 4 x + 5

y = \frac{1}{2} x^{2} + 9 x + 8