What is the directrix x=3y^2 ?

The directrix x=3y^2 is x=-1/12

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directrix x=3y^2

directrix

x = 3 y^{2}

x = - \frac{1}{12}

Solution steps

Rewrite

x = 3 y^{2}

in the standard form:

4 \cdot \frac{1}{12} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{12}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{12}

Refine

x = - \frac{1}{12}

y = x^{2} + 4 x - 1

y^{2} - 10 y - 12 x + 37 = 0

\frac{x}{25} - y^{2} = 1

y = x^{2} - 10 x - 31

3 x^{2} - 24 x - 15