What is the directrix+2.5t^2+6t ?

The directrix+2.5t^2+6t is y=-3.7

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directrix+2.5t^2+6t

directrix

+ 2.5 t^{2} + 6 t

y = - 3.7

Solution steps

Rewrite

y = 2.5 t^{2} + 6 t

in the standard form

4 \cdot 0.1 (y - (- 3.6)) = (t - (- 1.2))^{2}

(h, k) = (- 1.2, - 3.6), p = 0.1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 1.2, - 3.6)

y-coordinate

y = - 3.6 - p

y = - 3.6 - 0.1

Refine

y = - 3.7

y = x^{2} + 6 x + 8

- 5 t^{2} + 20 t

y = - (x - 2)^{2} + 4

y^{2} - 2 y - 12 x + 25 = 0

y^{2} - 6 x - y + 11 = 0