What is the directrix 4(x+1)^2 ?

The directrix 4(x+1)^2 is y=-1/16

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directrix 4(x+1)^2

directrix

4 (x + 1)^{2}

y = - \frac{1}{16}

Solution steps

Rewrite

y = 4 (x + 1)^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - (- 1))^{2}

(h, k) = (- 1, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 1, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{16}

Refine

y = - \frac{1}{16}

x^{2} + 5 x - 24

\frac{1}{24} y^{2}

y = 25 x^{2} - 70 x + 36

- 3 x^{2} + 5 x

y = - x^{2} - 4 x - 3