What is the directrix 4y^2-3x=0 ?

The directrix 4y^2-3x=0 is x=-3/16

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directrix 4y^2-3x=0

directrix

4 y^{2} - 3 x = 0

x = - \frac{3}{16}

Solution steps

Rewrite

4 y^{2} - 3 x = 0

in the standard form:

4 \cdot \frac{3}{16} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{3}{16}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{3}{16}

Refine

x = - \frac{3}{16}

y^{2} + 8 x - 4 y + 20 = 0

x = (y - 3)^{2} - 4

- 30 x^{2} + 28 x - 6

y^{2} - 20 x = 0

x^{2} = 100 y