What is the directrix y=(x^2)/(28)-(5x)/(14)+333/28 ?

The directrix y=(x^2)/(28)-(5x)/(14)+333/28 is y=4

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directrix y=(x^2)/(28)-(5x)/(14)+333/28

directrix

y = \frac{x ^{2}}{28} - \frac{5 x}{14} + \frac{333}{28}

y = 4

Solution steps

Rewrite

y = \frac{x ^{2}}{28} - \frac{5 x}{14} + \frac{333}{28}

in the standard form

4 \cdot 7 (y - 11) = (x - 5)^{2}

(h, k) = (5, 11), p = 7

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(5, 11)

y-coordinate

y = 11 - p

y = 11 - 7

Refine

y = 4

y = 3 x^{2} + x - 1

y = x^{2} - 5 x + 6

y = x^{2} - 5 x + 3

(x - 1)^{2} = 4 (y - 1)

(x - 6)^{2} = 8 (y - 2)

What is the directrix y=(x^2)/(28)-(5x)/(14)+333/28 ?
The directrix y=(x^2)/(28)-(5x)/(14)+333/28 is y=4