What is the directrix 5x+3y^2=0 ?

The directrix 5x+3y^2=0 is x= 5/12

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directrix 5x+3y^2=0

directrix

5 x + 3 y^{2} = 0

x = \frac{5}{12}

Solution steps

Rewrite

5 x + 3 y^{2} = 0

in the standard form:

4 (- \frac{5}{12}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{5}{12}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{5}{12})

Refine

x = \frac{5}{12}

+ (x - 1)^{2} + 2

3 - 4 x^{2}

2 y^{2} - 5 y + x - 4 = 0

x^{2} + 2 x - 8

x^{2} + 2 x - 1