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Popular >

foci y^2=-16x

Solution

foci

y^{2} = - 16 x

Solution

(- 4, 0)

Solution steps

Rewrite

y^{2} = - 16 x

in the standard form:

4 (- 4) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- 4), 0)

Refine

(- 4, 0)

Popular Examples

asymptotes of (x^2)/9-(y^2)/4 =1 asymptotes

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

vertices f(x)=-3x^2+12x-8 vertices

f (x) = - 3 x^{2} + 12 x - 8

vertices 9x^2+y^2=9 vertices

9 x^{2} + y^{2} = 9

directrix y=x^2 directrix

y = x^{2}

foci x^2=2y foci

x^{2} = 2 y

Frequently Asked Questions (FAQ)

What is the foci y^2=-16x ?
The foci y^2=-16x is (-4,0)