What is the directrix 3y^2=-4x ?

The directrix 3y^2=-4x is x= 1/3

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directrix 3y^2=-4x

directrix

3 y^{2} = - 4 x

x = \frac{1}{3}

Solution steps

Rewrite

3 y^{2} = - 4 x

in the standard form:

4 (- \frac{1}{3}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{3}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{3})

Refine

x = \frac{1}{3}

(x + 3)^{2} = 4 (y - 1)

y = x^{2} - 4 x - 3

y = - x^{2} + 6 x

y = x^{2} - 4 x + 5

- 2 x^{2} - 3 x - 1