What is the directrix y=+(x+6)^2 ?

The directrix y=+(x+6)^2 is y=-1/4

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directrix y=+(x+6)^2

directrix

y = + (x + 6)^{2}

y = - \frac{1}{4}

Solution steps

Rewrite

y = (x + 6)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - (- 6))^{2}

(h, k) = (- 6, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 6, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4}

Refine

y = - \frac{1}{4}

y = - 0.5 x^{2} - 3

4 x^{2} + 48 y + 12 x = 159

(x - 3)^{2} = - 8 (y + 2)

4 x^{2} - 2 x

y = - x^{2} + 18 x - 79