What is the directrix y^2+12x+8y-44=0 ?

The directrix y^2+12x+8y-44=0 is x=8

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directrix y^2+12x+8y-44=0

directrix

y^{2} + 12 x + 8 y - 44 = 0

x = 8

Solution steps

Rewrite

y^{2} + 12 x + 8 y - 44 = 0

in the standard form

4 (- 3) (x - 5) = (y - (- 4))^{2}

(h, k) = (5, - 4), p = - 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(5, - 4)

x-coordinate

x = 5 - p

x = 5 - (- 3)

Refine

x = 8

290 (8 x + 0.5 x^{2} - 1.4)

x^{2} - x

+ 4 x^{2} - 4 x + 9

x^{2} - 2

4 - (x - 3)^{2}