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Popular >

1=x^2+y^2

Solution

1 = x^{2} + y^{2}

Solution

(a, b) = (0, 0), r = 1

Solution steps

1 = x^{2} + y^{2}

Rewrite

1 = x^{2} + y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

Popular Examples

vertices x^2=-4y vertices

x^{2} = - 4 y

x^{2} - y^{2} = 9

x^2+y^2+4x-6y+12=0

x^{2} + y^{2} + 4 x - 6 y + 12 = 0

directrix x^2=16y directrix

x^{2} = 16 y

vertices f(x)=-x^2+6x+7 vertices

f (x) = - x^{2} + 6 x + 7

Frequently Asked Questions (FAQ)

What is 1=x^2+y^2 ?
The solution to 1=x^2+y^2 is Circle with (a,b)=(0,0),r=1