What is the directrix-3x^2 ?

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directrix-3x^2

directrix

- 3 x^{2}

y = \frac{1}{12}

Solution steps

Rewrite

y = - 3 x^{2}

in the standard form:

4 (- \frac{1}{12}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{12})

Refine

y = \frac{1}{12}

x^{2} - 8 x + 24

y = (x - 1)^{2} + 3

+ y = x^{2} + 2 x - 3

8 - 3 x - 2 x^{2}

(x + 2)^{2} = - 12 (y - 5)