What is the directrix y^2+36x=0 ?

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directrix y^2+36x=0

directrix

y^{2} + 36 x = 0

x = 9

Solution steps

Rewrite

y^{2} + 36 x = 0

in the standard form:

4 (- 9) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 9

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 9)

Refine

x = 9

(y - 3)^{2} = - 2 (x + 2)

y = (x + 314)^{2}

y = x^{2} - 13 x + 40

(x + 2)^{2} = - 8 (y - 1)

\frac{x ( x + 5 )}{7}