What is the directrix (y-0)^2=-4*sqrt(0.01)(x-0) ?

The directrix (y-0)^2=-4*sqrt(0.01)(x-0) is x=0.1

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directrix (y-0)^2=-4*sqrt(0.01)(x-0)

directrix

(y - 0)^{2} = - 4 \cdot 0.01 (x - 0)

x = 0.1

Solution steps

Rewrite

(y - 0)^{2} = - 4 0.01 (x - 0)

in the standard form:

4 (- 0.1) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 0.1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 0.1)

Refine

x = 0.1

3 x^{2} - 10 x + 3

2 y^{2} + 8 x = 0

(x - 2)^{2} = 4 (y + 2)

y = 3 x^{2} - 12 x + 5

(y - 2)^{2} = k (x - 3)

What is the directrix (y-0)^2=-4*sqrt(0.01)(x-0) ?
The directrix (y-0)^2=-4*sqrt(0.01)(x-0) is x=0.1