What is the directrix 25x^2-10x-200y-119=0 ?

The directrix 25x^2-10x-200y-119=0 is y=-13/5

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directrix 25x^2-10x-200y-119=0

directrix

25 x^{2} - 10 x - 200 y - 119 = 0

y = - \frac{13}{5}

Solution steps

Rewrite

25 x^{2} - 10 x - 200 y - 119 = 0

in the standard form

4 \cdot 2 (y - (- \frac{3}{5})) = (x - \frac{1}{5})^{2}

(h, k) = (\frac{1}{5}, - \frac{3}{5}), p = 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{5}, - \frac{3}{5})

y-coordinate

y = - \frac{3}{5} - p

y = - \frac{3}{5} - 2

Refine

y = - \frac{13}{5}

(y - 2)^{2} = - x - 3

2 x^{2} (2 + 1)

y = x^{2} + 16 x + 64

(x - 6)^{2} = 8 (y + 4)

y = - 3 x^{2} - 42 x - 22

What is the directrix 25x^2-10x-200y-119=0 ?
The directrix 25x^2-10x-200y-119=0 is y=-13/5