What is the directrix (x+5)^2=3(y-3) ?

The directrix (x+5)^2=3(y-3) is y= 9/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix (x+5)^2=3(y-3)

directrix

(x + 5)^{2} = 3 (y - 3)

y = \frac{9}{4}

Solution steps

Rewrite

(x + 5)^{2} = 3 (y - 3)

in the standard form:

4 \cdot \frac{3}{4} (y - 3) = (x - (- 5))^{2}

(h, k) = (- 5, 3), p = \frac{3}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 5, 3)

y-coordinate

y = 3 - p

y = 3 - \frac{3}{4}

Refine

y = \frac{9}{4}

12 (x - 2) = (y + 2)^{2}

y = - 5 x^{2}

x^{2} + 8 x - 8 y + 8 = 0

y = - 3 x^{2} + 17 x - 20

92 x^{2}