What is the directrix-x^2-4x+2 ?

The directrix-x^2-4x+2 is y= 25/4

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directrix-x^2-4x+2

directrix

- x^{2} - 4 x + 2

y = \frac{25}{4}

Solution steps

Rewrite

y = - x^{2} - 4 x + 2

in the standard form

4 (- \frac{1}{4}) (y - 6) = (x - (- 2))^{2}

(h, k) = (- 2, 6), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 2, 6)

y-coordinate

y = 6 - p

y = 6 - (- \frac{1}{4})

Refine

y = \frac{25}{4}

y = x^{2} - 6 x

y^{2} + 4 x = 0

y^{2} = \frac{- 16}{5} x

y = (2 X + 5) (3 X - 7)

(y + 2)^{2} = - 16 (x + 9)