What is the directrix 1/8 x^2 ?

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directrix 1/8 x^2

directrix

\frac{1}{8} x^{2}

y = - 2

Solution steps

Rewrite

y = \frac{1}{8} x^{2}

in the standard form:

4 \cdot 2 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 2

Refine

y = - 2

x^{2} + 8 x - 4 y - 36 = 0

\frac{1}{400} x^{2} - x + 150

y = (x - 1) (3 x + 1)

y = - x^{2} - 4 x + 6

2 (x - 3)^{2} + 6