What is the directrix 3x^2+4 ?

The directrix 3x^2+4 is y= 47/12

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directrix 3x^2+4

directrix

3 x^{2} + 4

y = \frac{47}{12}

Solution steps

Rewrite

y = 3 x^{2} + 4

in the standard form:

4 \cdot \frac{1}{12} (y - 4) = (x - 0)^{2}

(h, k) = (0, 4), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 4)

y-coordinate

y = 4 - p

y = 4 - \frac{1}{12}

Refine

y = \frac{47}{12}

3 x^{2} + 2

5 x^{2} + 7 y = 3

x = 4 y^{2} + 12 y + 9

7 x^{2} - 5 x + 9

- 8 x^{2} + 4 x