What is the directrix y=-8x^2 ?

The directrix y=-8x^2 is y= 1/32

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directrix y=-8x^2

directrix

y = - 8 x^{2}

y = \frac{1}{32}

Solution steps

Rewrite

y = - 8 x^{2}

in the standard form:

4 (- \frac{1}{32}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{32}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{32})

Refine

y = \frac{1}{32}

3 x^{2} - x

x^{2} + 14 x + 46

- 3 x^{2} + 17 x - 20

y + 1 = 5 (x - 2)^{2}

y = 4 x^{2} + 5