What is the directrix (x+4)^2-3 ?

The directrix (x+4)^2-3 is y=-13/4

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directrix (x+4)^2-3

directrix

(x + 4)^{2} - 3

y = - \frac{13}{4}

Solution steps

Rewrite

y = (x + 4)^{2} - 3

in the standard form:

4 \cdot \frac{1}{4} (y - (- 3)) = (x - (- 4))^{2}

(h, k) = (- 4, - 3), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 4, - 3)

y-coordinate

y = - 3 - p

y = - 3 - \frac{1}{4}

Refine

y = - \frac{13}{4}

x^{2} + 12 x + 6 y + 10 = 0

y = (2 x + 1)^{2} - 1

(x - 3) (x - 7)

- (x - 1)^{2} + 5

1.5 + 17.67 t - 4.905 t^{2}