What is the directrix y=-16x^2+16x+480 ?

The directrix y=-16x^2+16x+480 is y= 30977/64

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directrix y=-16x^2+16x+480

directrix

y = - 16 x^{2} + 16 x + 480

y = \frac{30977}{64}

Solution steps

Rewrite

y = - 16 x^{2} + 16 x + 480

in the standard form

4 (- \frac{1}{64}) (y - 484) = (x - \frac{1}{2})^{2}

(h, k) = (\frac{1}{2}, 484), p = - \frac{1}{64}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{2}, 484)

y-coordinate

y = 484 - p

y = 484 - (- \frac{1}{64})

Refine

y = \frac{30977}{64}

- x^{2} + 5 x - 7

(x - 1)^{2} = 8 (y + 3)

+ 3 x^{2}

(x + 1)^{2} = 12 (y - 3)

5 x - x^{2}

What is the directrix y=-16x^2+16x+480 ?
The directrix y=-16x^2+16x+480 is y= 30977/64