What is the foci (x^2)/(144)+(y^2)/(169)=1 ?

The foci (x^2)/(144)+(y^2)/(169)=1 is (0,5),(0,-5)

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foci (x^2)/(144)+(y^2)/(169)=1

foci

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 13, a = 12

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 3^{2} - 1 2^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

x^{2} + y = 0

x^{2} - 4 y^{2} = 4

4 x^{2} - 12 x - 16 y + 41 = 0

2 y^{2} - 8 x - 24 y + 56 = 0

What is the foci (x^2)/(144)+(y^2)/(169)=1 ?
The foci (x^2)/(144)+(y^2)/(169)=1 is (0,5),(0,-5)