What is the directrix (x-h)^2=4(-8)(y-3) ?

The directrix (x-h)^2=4(-8)(y-3) is y=11

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directrix (x-h)^2=4(-8)(y-3)

directrix

(x - h)^{2} = 4 (- 8) (y - 3)

y = 11

Solution steps

Rewrite

(x - h)^{2} = 4 (- 8) (y - 3)

in the standard form:

4 (- 8) (y - 3) = (x - h)^{2}

(h, k) = (h, 3), p = - 8

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(h, 3)

y-coordinate

y = 3 - p

y = 3 - (- 8)

Refine

y = 11

100 + 6 x^{2} - 8 x

x^{2} - 6 x + 5

- (x + 3)^{2} - 1

- x^{2} - 2 x - 3

- x^{2} - 2 x - 1

What is the directrix (x-h)^2=4(-8)(y-3) ?
The directrix (x-h)^2=4(-8)(y-3) is y=11