What is the directrix y^2-8x-8y+24=0 ?

The directrix y^2-8x-8y+24=0 is x=-1

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directrix y^2-8x-8y+24=0

directrix

y^{2} - 8 x - 8 y + 24 = 0

x = - 1

Solution steps

Rewrite

y^{2} - 8 x - 8 y + 24 = 0

in the standard form

4 \cdot 2 (x - 1) = (y - 4)^{2}

(h, k) = (1, 4), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(1, 4)

x-coordinate

x = 1 - p

x = 1 - 2

Refine

x = - 1

y = + x^{2} - 4 x - 32

x^{2} + 2 x + 2

y = x^{2} - 2 x - 15

x^{2} - 10000 x - 24000000

y = - 3 x^{2} - 12 x - 17