What is the directrix 16x^2-25 ?

The directrix 16x^2-25 is y=-1601/64

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directrix 16x^2-25

directrix

16 x^{2} - 25

y = - \frac{1601}{64}

Solution steps

Rewrite

y = 16 x^{2} - 25

in the standard form:

4 \cdot \frac{1}{64} (y - (- 25)) = (x - 0)^{2}

(h, k) = (0, - 25), p = \frac{1}{64}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 25)

y-coordinate

y = - 25 - p

y = - 25 - \frac{1}{64}

Refine

y = - \frac{1601}{64}

- x^{2} + 64 x - 292

y = 5 x^{2} + 13 x - 6

y = 3 x^{2} + 6 x - 12

(x - 5)^{2} = 20 (y - 5)

x^{2} = 4 (y - 2)