What is the directrix x^2-12x+35 ?

The directrix x^2-12x+35 is y=-5/4

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directrix x^2-12x+35

directrix

x^{2} - 12 x + 35

y = - \frac{5}{4}

Solution steps

Rewrite

y = x^{2} - 12 x + 35

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 6)^{2}

(h, k) = (6, - 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(6, - 1)

y-coordinate

y = - 1 - p

y = - 1 - \frac{1}{4}

Refine

y = - \frac{5}{4}

x = (2 y + 5)^{2}

6 x^{2} - 12 x

y = (x + 1)^{2} + 1

y = (x + 1)^{2} + 5

t^{2} + 2