What is the directrix x=-5y^2 ?

The directrix x=-5y^2 is x= 1/20

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directrix x=-5y^2

directrix

x = - 5 y^{2}

x = \frac{1}{20}

Solution steps

Rewrite

x = - 5 y^{2}

in the standard form:

4 (- \frac{1}{20}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{20}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{20})

Refine

x = \frac{1}{20}

y = (- x - 1) (x + 3)

2 (y - 1)^{2} - 4

x = - \frac{1}{2} (y - 2)^{2} + 5

y = 48 x - 8 x^{2}

x^{2} + 4 x + 4 y = - 4