What is (x-2)^2+y^2=16 ?

The solution to (x-2)^2+y^2=16 is Circle with (a,b)=(2,0),r=4

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(x-2)^2+y^2=16

(x - 2)^{2} + y^{2} = 16

(a, b) = (2, 0), r = 4

Solution steps

(x - 2)^{2} + y^{2} = 16

Rewrite

(x - 2)^{2} + y^{2} = 16

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 4

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

x^{2} + y^{2} - 12 y + 32 = 0

9 (y - 2)^{2} - 4 x^{2} = 36

x^{2} + 9 y^{2} = 9

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

What is (x-2)^2+y^2=16 ?
The solution to (x-2)^2+y^2=16 is Circle with (a,b)=(2,0),r=4