What is the directrix 11x^2+13 ?

The directrix 11x^2+13 is y= 571/44

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directrix 11x^2+13

directrix

11 x^{2} + 13

y = \frac{571}{44}

Solution steps

Rewrite

y = 11 x^{2} + 13

in the standard form:

4 \cdot \frac{1}{44} (y - 13) = (x - 0)^{2}

(h, k) = (0, 13), p = \frac{1}{44}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 13)

y-coordinate

y = 13 - p

y = 13 - \frac{1}{44}

Refine

y = \frac{571}{44}

- 2 (x + 3) = (y - 1)^{2}

2 y^{2} = - 5 x

12 (x - 1) = (y - 3)^{2}

y = \frac{1}{4} x^{2} - \frac{5}{2} x + \frac{13}{4}

4 x^{2} - 25