What is the directrix y=-6x^2+37x+13 ?

The directrix y=-6x^2+37x+13 is y= 841/12

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directrix y=-6x^2+37x+13

directrix

y = - 6 x^{2} + 37 x + 13

y = \frac{841}{12}

Solution steps

Rewrite

y = - 6 x^{2} + 37 x + 13

in the standard form

4 (- \frac{1}{24}) (y - \frac{1681}{24}) = (x - \frac{37}{12})^{2}

(h, k) = (\frac{37}{12}, \frac{1681}{24}), p = - \frac{1}{24}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{37}{12}, \frac{1681}{24})

y-coordinate

y = \frac{1681}{24} - p

y = \frac{1681}{24} - (- \frac{1}{24})

Refine

y = \frac{841}{12}

x^{2} = - 24 y

y = - 9 x^{2} + 2

x^{2} - 12 x + 1

y = (2 x + 3)^{2}

3 x^{2} + 7 x + 1

What is the directrix y=-6x^2+37x+13 ?
The directrix y=-6x^2+37x+13 is y= 841/12