What is the directrix y+8x^2=0 ?

The directrix y+8x^2=0 is y= 1/32

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directrix y+8x^2=0

directrix

y + 8 x^{2} = 0

y = \frac{1}{32}

Solution steps

Rewrite

y + 8 x^{2} = 0

in the standard form:

4 (- \frac{1}{32}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{32}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{32})

Refine

y = \frac{1}{32}

- 3 (x - 7)^{2}

(x + 7)^{2} = 5 (y + 3)

y^{2} - 6 y = - 4 x + 3

+ x^{2} - 14

x^{2} + 8 x + 3