What is the directrix (x-6)^2 ?

The directrix (x-6)^2 is y=-1/4

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directrix (x-6)^2

directrix

(x - 6)^{2}

y = - \frac{1}{4}

Solution steps

Rewrite

y = (x - 6)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 6)^{2}

(h, k) = (6, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(6, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4}

Refine

y = - \frac{1}{4}

(x - 2)^{2} = 2 (y + 2)

x = - \frac{( y + 3 ) ^{2}}{20} + 1

2 x^{2} - 4

y = \frac{1}{2} (x + 1)^{2} + 4

(y - 6)^{2} = 36 (x - 2)