What is the directrix (x-0)^2=4y-4 ?

The directrix (x-0)^2=4y-4 is y=0

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directrix (x-0)^2=4y-4

directrix

(x - 0)^{2} = 4 y - 4

y = 0

Solution steps

Rewrite

(x - 0)^{2} = 4 y - 4

in the standard form:

4 \cdot 1 \cdot (y - 1) = (x - 0)^{2}

(h, k) = (0, 1), p = 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 1)

y-coordinate

y = 1 - p

y = 1 - 1

Refine

y = 0

y = x + x^{2}

4 x - 11 y^{2} = 0

+ (y - 2) = 3 (x - 5)^{2}

x^{2} = 16 (y - 9)

(x - 4)^{2} = - 4 (y + 2)