What is the directrix y^2-4x=0 ?

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directrix y^2-4x=0

directrix

y^{2} - 4 x = 0

x = - 1

Solution steps

Rewrite

y^{2} - 4 x = 0

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 1

Refine

x = - 1

x^{2} - 6

4 x^{2} + 3 x - 1

x^{2} + a

y = - \frac{1}{4} (x^{2} - 14 x + 13)

x^{2} + 5