What is the directrix 2x^2+16x+35 ?

The directrix 2x^2+16x+35 is y= 23/8

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directrix 2x^2+16x+35

directrix

2 x^{2} + 16 x + 35

y = \frac{23}{8}

Solution steps

Rewrite

y = 2 x^{2} + 16 x + 35

in the standard form

4 \cdot \frac{1}{8} (y - 3) = (x - (- 4))^{2}

(h, k) = (- 4, 3), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 4, 3)

y-coordinate

y = 3 - p

y = 3 - \frac{1}{8}

Refine

y = \frac{23}{8}

y = 40 x - 5 x^{2}

4 y^{2} + 3 x = 0

(x - 1)^{2} = y - 2

x^{2} - 4 x + 2

x^{2} - 4 x + 3