What is the directrix x=-3y^2 ?

The directrix x=-3y^2 is x= 1/12

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directrix x=-3y^2

directrix

x = - 3 y^{2}

x = \frac{1}{12}

Solution steps

Rewrite

x = - 3 y^{2}

in the standard form:

4 (- \frac{1}{12}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{12}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{1}{12})

Refine

x = \frac{1}{12}

- 0.2 t^{2} + 2.4 t + 98.6

x^{2} + 2 x - 8 y + 33 = 0

6 x^{2} - 6 x

(x - \frac{5}{2})^{2} = 7 (y + 3.75)

y = - x^{2} + 8 x - 18