What is the directrix y=(2x-1)^2 ?

The directrix y=(2x-1)^2 is y=-1/16

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directrix y=(2x-1)^2

directrix

y = (2 x - 1)^{2}

y = - \frac{1}{16}

Solution steps

Rewrite

y = (2 x - 1)^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - \frac{1}{2})^{2}

(h, k) = (\frac{1}{2}, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{2}, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{16}

Refine

y = - \frac{1}{16}

y = - 12 x^{2} - 29 x + 230

y = x^{2} - 5 x 3

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

x = (y + 1) y

(x - 9)^{2} - 6