What is the directrix y^2=12(x-4) ?

The directrix y^2=12(x-4) is x=1

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directrix y^2=12(x-4)

directrix

y^{2} = 12 (x - 4)

x = 1

Solution steps

Rewrite

y^{2} = 12 (x - 4)

in the standard form:

4 \cdot 3 (x - 4) = (y - 0)^{2}

(h, k) = (4, 0), p = 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(4, 0)

x-coordinate

x = 4 - p

x = 4 - 3

Refine

x = 1

2 x^{2} - 4 x - 9

y = 4 x^{2} - 2 x + 4

x^{2} = 4 y + 8

\frac{9 x ^{2}}{2}

2 x^{2} + 8 x + 13