What is the directrix (x-3)^2=y-7 ?

The directrix (x-3)^2=y-7 is y= 27/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix (x-3)^2=y-7

directrix

(x - 3)^{2} = y - 7

y = \frac{27}{4}

Solution steps

Rewrite

(x - 3)^{2} = y - 7

in the standard form:

4 \cdot \frac{1}{4} (y - 7) = (x - 3)^{2}

(h, k) = (3, 7), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, 7)

y-coordinate

y = 7 - p

y = 7 - \frac{1}{4}

Refine

y = \frac{27}{4}

(x - 3)^{2} = 12 (y - 2)

y = 2 x^{2} + 9 x - 3

y = x^{2} + 8 x - 5

(y - 0)^{2} = - 43 (x - 0)

y = x^{2} + 22