What is the directrix y^2-6y+3 ?

The directrix y^2-6y+3 is x=-25/4

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directrix y^2-6y+3

directrix

y^{2} - 6 y + 3

x = - \frac{25}{4}

Solution steps

Rewrite

x = y^{2} - 6 y + 3

in the standard form

4 \cdot \frac{1}{4} (x - (- 6)) = (y - 3)^{2}

(h, k) = (- 6, 3), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 6, 3)

x-coordinate

x = - 6 - p

x = - 6 - \frac{1}{4}

Refine

x = - \frac{25}{4}

3 y^{2} + 4 x - 24 y + 44 = 0

y = (x - 4) (x - 2)

(x - 4)^{2} - 2 (y + 8) = 0

+ \frac{2 h ^{3} + 4 h ^{2} + 5 h}{h}

x^{2} + 6 x - 8