What is the directrix 1/8 x^2-y=0 ?

The directrix 1/8 x^2-y=0 is y=-2

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directrix 1/8 x^2-y=0

directrix

\frac{1}{8} x^{2} - y = 0

y = - 2

Solution steps

Rewrite

\frac{1}{8} x^{2} - y = 0

in the standard form:

4 \cdot 2 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 2

Refine

y = - 2

y = - 2 x^{2} - 3

x^{2} - 2 x - 4 y + 17 = 0

x^{2} - 12 y - 6 x + 5 = 0

x^{2} + 4 x - y + 1 = 0

3 x^{2} - 4 x - 2