What is 36x^2+36y^2-12x-27y-8=0 ?

The solution to 36x^2+36y^2-12x-27y-8=0 is Circle with (a,b)=(1/6 , 3/8),r= 5/8

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36x^2+36y^2-12x-27y-8=0

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

(a, b) = (\frac{1}{6}, \frac{3}{8}), r = \frac{5}{8}

Solution steps

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

Rewrite

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

in the form of the standard circle equation

(x - \frac{1}{6})^{2} + (y - \frac{3}{8})^{2} = (\frac{5}{8})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{6}, \frac{3}{8}), r = \frac{5}{8}

y^{2} = 2 x

y^{2} - 3 y - x + 3 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

y^{2} + x + y = 0

x^{2} = 28 y

What is 36x^2+36y^2-12x-27y-8=0 ?
The solution to 36x^2+36y^2-12x-27y-8=0 is Circle with (a,b)=(1/6 , 3/8),r= 5/8