What is the directrix x-y^2=0 ?

The directrix x-y^2=0 is x=-1/4

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directrix x-y^2=0

directrix

x - y^{2} = 0

x = - \frac{1}{4}

Solution steps

Rewrite

x - y^{2} = 0

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{4}

Refine

x = - \frac{1}{4}

9 x^{2} - 4

- x^{2} + 8 x - 15

y = - (x - 4)^{2} + 1

- 12 y + 10 = x^{2} - 4 x + 14

- 2 x^{2} + 11